31 gm of ethylene glycol (C2H6O2) is mi...

31 gm of ethylene glycol `(C_2H_6O_2)` is mixed with 500 gm of solvent. `(K_f = 2 K kg "mol"^(-1))`. What is the freezing point of the solution in K ? (freezing point of solvent = 273K)

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Verified by Experts

The correct Answer is:

Hint : `DeltaT_f = k_f xxW_B xx(k_fxxW_Bxx1000)/(M_BxxW_A)`
`implies(2xx31 xx1000)/(62 xx500) =2 K`
`DeltaT_f = T_f^@ - T_f = 2 `

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