18 g of glucose is dissolved in 1 kg of ...

18 g of glucose is dissolved in 1 kg of water. At what temperature will the solution boil ? ( `K_b` for water is 0.52 K kg `"mol"^(-1)`)

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`W_B=18 g`, Mp(glucose, `C_6H_(12)O_(6) =180, W_A=1 kg, K_b = 0.52 K "kg mol"^(-1)`
`DeltaT_b = K_bm` (From-Elevation in boiling point equation)
`:. DeltaT_b=K_bxx(W_B)/(M_B)xx1/(W_A(kg))=0.52xx18/180xx1/1=0.052K`
`DeltaT_b= 0.0052^@C`
Boiling point of solution
`T _b= T_b^@ +DeltaT_b" "[DeltaT_b = T_b-T_b^@]`
`TDelta_b= 0.0052^@C`

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