How many grams of ethylene glycol (molar mass = 62) should be added to 10 kg of water, so that the resulting solution freezes at `-10^(@)C` (`K_(f)` for water = 1.86 K `"mol^(-1)`).

Explanation

`W_B=?, M_B=62 "g mol"^(-1), W_A= 10 kg, K_f = 1.86 "K mol"^(-1)`
`DeltaT_f = 0 -(-10^@C) = 10^@C`
`DeltaT_f=10K`
`DeltaT_f=K_f xx(W_B)/(M_B)xx1/(W_A(kg))`
`W_B = (DeltaT_f xxM_B xxW_A(kg))/(K_f)`
`= (10 K xx62 " g mol"^(-1)xx10 kg )/(1.86 "KK g.mol"^(-1)) = 3.33 ` kg