The density of `10% ` by mass of KCI solution in water is ` 1 . 0 6 g mL^(-1)` . Calculate molarity and molality of the solution

Explanation

Moles of solute = `(10)/(73.5)`
= 0.136
Volume of `"sol"^n = M/rho = 100/(1.06)`
= 94.33
Molarity = `("Moles of Solute")/("Volume of sol"^n)xx1000`
`= (0.136)/(94.33) xx1000`
Mass of solvent = 90 g
Molality = `("Moles of Solute")/("Mass of Solvent")xx1000`
`= (0.136)/(90)xx1000=1.5m`