18 g of a compound is dissolved in 10 kg of water so that the resulting solution freezes at ` - 8^(@) C`. If `K_(f)` for water = 1 . 86 K/m . Calculate the molecular mass of the compound

Explanation

`W_B= 18 g`
` W_A = 1 kg = 1000g`
`K_f= 1.86`
`DeltaT_f =-8^@C`
`M_B=(K_fxxW_Bxx1000)/(W_AxxDeltaT_f)`
`= (1.86xx18xx1000)/(1000xx8)`
`=(38480)/(8000)`
`=4.185`
`=4.2 mu`