Calculate mole fraction of water in a mixture of 12 g of water and 92 g ethanol.

Explanation

Males of water (A) = `12/8`
= 0.666
Moles of Ethanol (B) = `(92)/46`
= 2
`x_A=("Moles of A")/("Moles of A + Moles of B")`
`=(0.666)/(0.666 +2)`
`= (0.666)/(2.666)`
= 0.25