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If 1 .71 g of sugar (molar mass = 342) a...

If 1 .71 g of sugar (molar mass = 342) are dissolved in `500 cm^(3)` of solution at 300 K, what will be its osmotic pressure ?

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Give mass = 1.71g
Molar Mass = 342 g
`V = 500 "cm"^3`
`=0.5V`
T = 300 K
R = 0.083
`pi ` = CRT
`=n/VRT`
`= (0.005)/(0.5)xx0.083 xx 300`
= 0.249 bar.
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