Concentrated `H_(2)SO_(4)` has a density 1 . 9 g/mL and is ` 99% H_(2) SO_(4)` by mass. Calculate the molarity of the acid

Explanation

`rho = 1.9 ` g/mL
Given mass = 99 g
Moles of solute `= (99)/98`
`= 1.010`
`rho = M/V`
Let M = 100 g
`V = (100)/(1.9) = 52.63 ` ml
Molarity `=("Moles of Solute")/("Volume of sol"^(n))xx1000`
`= (1.010)/(52.63)xx1000`
`= 19.19M`