square and cube

If S_1, S_2, S_3 are the sums of first n natural numbers, their squares and cubes respectively, show that 9S_2^ 2=S_3(1+8S_1)dot

Natural numbers ke square aur cube sum nikalna seekhen humare sath

The number of two digit numbers which are perfect square and perfect cube both is :

The product of the digits of a three digit number which is a perfect square and perfect cube both is :

A number 1 < N < 100 is such that it is a perfect square and perfect cube both, then the sum of digits of N is :

A number 1 lt N lt 100 is such that it is a perfect square and perfect cube both, then the sum of digits of N is :

If S_(1),S_(2),S_(3) are the sums of first n natural numbers,their squares and their cubes respectively then S_(3)(1+8S_(1))=

If quad S_(1),S_(2),S_(3) are the sum of first n natural numbers,their squares and their cubes,respectively,show that 9S_(2)^(2)=S_(3)(1+8S_(1))