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47 is added to the product of 71 and an ...

47 is added to the product of 71 and an unknown number. The new number is divisible by 7 giving the quotient 98. The unknown number is a multiple of

A

2

B

5

C

7

D

3

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The correct Answer is:
To solve the problem step by step, we can break it down as follows: ### Step 1: Understand the problem We are given that 47 is added to the product of 71 and an unknown number \( x \). The resulting number is divisible by 7, and the quotient when this number is divided by 7 is 98. ### Step 2: Set up the equation From the information given, we can set up the equation: \[ 71x + 47 = 7 \times 98 \] ### Step 3: Calculate the right side of the equation Now, calculate \( 7 \times 98 \): \[ 7 \times 98 = 686 \] So, we can rewrite our equation as: \[ 71x + 47 = 686 \] ### Step 4: Isolate the unknown number \( x \) Next, we need to isolate \( x \). We can do this by subtracting 47 from both sides: \[ 71x = 686 - 47 \] Calculating the right side: \[ 686 - 47 = 639 \] So, we have: \[ 71x = 639 \] ### Step 5: Solve for \( x \) Now, divide both sides by 71 to find \( x \): \[ x = \frac{639}{71} \] Calculating the division: \[ x = 9 \] ### Step 6: Determine if \( x \) is a multiple of the given options The problem states that the unknown number \( x \) is a multiple of something. Since we found \( x = 9 \), we can check if it is a multiple of the options provided (if any were given). ### Conclusion Thus, the unknown number \( x \) is 9. ---
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