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A number x when divided by 289 leaves 18...

A number x when divided by 289 leaves 18 as the remainder. The same number when divided by 17 leaves y as a remainder. The value of y is

A

a) 5

B

b) 2

C

c) 3

D

d) 1

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The correct Answer is:
To solve the problem, we need to find the value of \( y \) when the number \( x \) is divided by 17, given that \( x \) leaves a remainder of 18 when divided by 289. ### Step-by-Step Solution: 1. **Understanding the Problem:** We know that when \( x \) is divided by 289, it leaves a remainder of 18. This can be expressed mathematically as: \[ x = 289k + 18 \] where \( k \) is some integer. 2. **Finding \( x \) Modulo 17:** We need to find the remainder when \( x \) is divided by 17. To do this, we can substitute the expression for \( x \) into the modulo operation: \[ x \mod 17 = (289k + 18) \mod 17 \] 3. **Calculating \( 289 \mod 17 \):** First, we need to find \( 289 \mod 17 \): \[ 289 \div 17 = 17 \quad \text{(since } 17 \times 17 = 289\text{)} \] Therefore, the remainder is: \[ 289 \mod 17 = 0 \] 4. **Substituting Back:** Now we can substitute this back into our equation: \[ x \mod 17 = (0 \cdot k + 18) \mod 17 = 18 \mod 17 \] 5. **Calculating \( 18 \mod 17 \):** Now, we find \( 18 \mod 17 \): \[ 18 \div 17 = 1 \quad \text{(since } 17 \times 1 = 17\text{)} \] The remainder is: \[ 18 - 17 = 1 \] 6. **Conclusion:** Therefore, the value of \( y \) is: \[ y = 1 \] ### Final Answer: The value of \( y \) is \( 1 \).
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