In a division sum, the divisor is 3 times the quotient and 6 times the remainder. If the remainder Is 2, then the divjaend is

Options

A. 50
B. 48
C. 36
D. 28

Answer

To solve the problem step by step, let's denote the following variables:

- Let \( D \) be the divisor.
- Let \( Q \) be the quotient.
- Let \( R \) be the remainder.
- Let \( N \) be the dividend.

From the problem statement, we have the following relationships:

1. The divisor \( D \) is 3 times the quotient \( Q \):
\[ D = 3Q \]

2. The divisor \( D \) is also 6 times the remainder \( R \):
\[ D = 6R \]

3. The remainder \( R \) is given as 2:
\[ R = 2 \]

Now, we can substitute \( R \) into the second equation to find \( D \):
\[ D = 6R = 6 \times 2 = 12 \]

Next, we substitute \( D \) into the first equation to find \( Q \):
\[ 12 = 3Q \implies Q = \frac{12}{3} = 4 \]

Now we have the values for \( D \) and \( Q \):
- \( D = 12 \)
- \( Q = 4 \)
- \( R = 2 \)

Now we can use the formula for the dividend \( N \):
\[ N = D \times Q + R \]

Substituting the values we found:
\[ N = 12 \times 4 + 2 = 48 + 2 = 50 \]

Thus, the dividend \( N \) is:
\[ \boxed{50} \]