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How many numbers are there between 1 and...

How many numbers are there between 1 and 200 which are divisible by 3 but not by 7?

A

a) 38

B

b) 45

C

c) 57

D

d) 66

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding how many numbers between 1 and 200 are divisible by 3 but not by 7, we can follow these steps: ### Step 1: Find the total numbers divisible by 3 First, we need to determine how many numbers between 1 and 200 are divisible by 3. - The smallest number divisible by 3 in this range is 3. - The largest number divisible by 3 in this range is 198. To find the count of numbers divisible by 3, we can use the formula for the number of terms in an arithmetic sequence: \[ \text{Count} = \frac{\text{Largest} - \text{Smallest}}{\text{Common Difference}} + 1 \] Substituting our values: \[ \text{Count} = \frac{198 - 3}{3} + 1 = \frac{195}{3} + 1 = 65 + 1 = 66 \] So, there are **66 numbers** between 1 and 200 that are divisible by 3. ### Step 2: Find the total numbers divisible by both 3 and 7 Next, we need to find how many of these numbers are also divisible by 7. A number that is divisible by both 3 and 7 is divisible by their least common multiple (LCM). The LCM of 3 and 7 is 21. - The smallest number divisible by 21 in this range is 21. - The largest number divisible by 21 in this range is 189. Using the same formula: \[ \text{Count} = \frac{189 - 21}{21} + 1 \] Calculating this: \[ \text{Count} = \frac{168}{21} + 1 = 8 + 1 = 9 \] So, there are **9 numbers** between 1 and 200 that are divisible by both 3 and 7. ### Step 3: Subtract the numbers divisible by both 3 and 7 from those divisible by 3 Now, we subtract the numbers that are divisible by both 3 and 7 from the total numbers that are divisible by 3: \[ \text{Total divisible by 3 but not by 7} = \text{Total divisible by 3} - \text{Total divisible by both 3 and 7} \] Substituting the values: \[ \text{Total} = 66 - 9 = 57 \] Thus, there are **57 numbers** between 1 and 200 that are divisible by 3 but not by 7. ### Final Answer The final answer is **57**. ---
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