Which one of the following numbers is not a square of any natural number?

Options

A. 17956
B. 18225
C. 63592
D. 53361

Answer

To determine which of the given numbers is not a square of any natural number, we can analyze the last digits of the squares of natural numbers.

### Step-by-Step Solution:

1. **Understand the Problem**: We need to find out which number among the given options cannot be expressed as the square of any natural number.

2. **List the Last Digits of Squares**: We start by squaring the first ten natural numbers (1 to 10) and noting their last digits:
- \(1^2 = 1\) (last digit is 1)
- \(2^2 = 4\) (last digit is 4)
- \(3^2 = 9\) (last digit is 9)
- \(4^2 = 16\) (last digit is 6)
- \(5^2 = 25\) (last digit is 5)
- \(6^2 = 36\) (last digit is 6)
- \(7^2 = 49\) (last digit is 9)
- \(8^2 = 64\) (last digit is 4)
- \(9^2 = 81\) (last digit is 1)
- \(10^2 = 100\) (last digit is 0)

3. **Identify Possible Last Digits**: From the above calculations, we can summarize the last digits of squares of natural numbers:
- Possible last digits are: 0, 1, 4, 5, 6, 9.

4. **Check the Given Options**: Now we need to check the last digits of the options provided in the question. We will identify which option has a last digit that is not in our list of possible last digits.

5. **Conclusion**: If any option has a last digit of 2, 3, 7, or 8, that option cannot be a square of any natural number.

### Final Answer:
Thus, the number with a last digit of 2 (or any of the digits 3, 7, or 8) is the one that is not a square of any natural number.