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The value of (1+(1)/(2)) (1+(1)/(3))(1+(...

The value of `(1+(1)/(2)) (1+(1)/(3))(1+(1)/(4))....(1+(1)/(120))` is

A

30

B

`40.5`

C

`60.5`

D

`121`

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The correct Answer is:
To solve the expression \((1 + \frac{1}{2})(1 + \frac{1}{3})(1 + \frac{1}{4}) \ldots (1 + \frac{1}{120})\), we will follow these steps: ### Step 1: Rewrite Each Term Each term in the product can be rewritten as: \[ 1 + \frac{1}{n} = \frac{n + 1}{n} \] Thus, we can rewrite the entire expression as: \[ (1 + \frac{1}{2})(1 + \frac{1}{3})(1 + \frac{1}{4}) \ldots (1 + \frac{1}{120}) = \frac{3}{2} \cdot \frac{4}{3} \cdot \frac{5}{4} \cdots \frac{121}{120} \] ### Step 2: Write the Product Now, we can express the product more clearly: \[ = \frac{3 \cdot 4 \cdot 5 \cdots \cdot 121}{2 \cdot 3 \cdot 4 \cdots \cdot 120} \] ### Step 3: Simplify the Product Notice that in the numerator and denominator, many terms will cancel out: - The \(3\) in the numerator cancels with the \(3\) in the denominator. - The \(4\) in the numerator cancels with the \(4\) in the denominator. - This pattern continues up to \(120\). After cancellation, we are left with: \[ = \frac{121}{2} \] ### Step 4: Calculate the Final Value Now, we can compute the final value: \[ \frac{121}{2} = 60.5 \] ### Final Answer Thus, the value of the expression \((1 + \frac{1}{2})(1 + \frac{1}{3})(1 + \frac{1}{4}) \ldots (1 + \frac{1}{120})\) is: \[ \boxed{60.5} \]
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