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If two numbers x and y separately divide...

If two numbers x and y separately divided by a number d, remainders obtained are 4375 and 2986 respectively. If the sum of the numbers 1.e (x+y) is divided by the same number d remainder obtained is 2361. The value of number d is

A

7361

B

5000

C

4000

D

2542

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The correct Answer is:
To solve the problem, we need to find the value of the number \( d \) given the remainders when two numbers \( x \) and \( y \) are divided by \( d \), and the remainder when their sum \( x + y \) is divided by \( d \). ### Step-by-Step Solution: 1. **Understanding the Remainders:** - When \( x \) is divided by \( d \), the remainder is \( 4375 \). - When \( y \) is divided by \( d \), the remainder is \( 2986 \). - When \( x + y \) is divided by \( d \), the remainder is \( 2361 \). 2. **Expressing the Numbers:** - We can express \( x \) and \( y \) in terms of \( d \): \[ x = kd + 4375 \quad \text{(for some integer } k\text{)} \] \[ y = md + 2986 \quad \text{(for some integer } m\text{)} \] 3. **Finding the Sum:** - The sum \( x + y \) can be expressed as: \[ x + y = (kd + 4375) + (md + 2986) = (k + m)d + (4375 + 2986) \] - Simplifying the constant part: \[ 4375 + 2986 = 7361 \] - Therefore, we have: \[ x + y = (k + m)d + 7361 \] 4. **Using the Remainder of the Sum:** - When \( x + y \) is divided by \( d \), the remainder is given as \( 2361 \): \[ (k + m)d + 7361 \equiv 2361 \mod d \] - This implies: \[ 7361 \equiv 2361 \mod d \] 5. **Finding the Difference:** - We can find the difference: \[ 7361 - 2361 = 5000 \] - Therefore, we have: \[ 7361 - 2361 = 5000 \equiv 0 \mod d \] - This means \( d \) must be a divisor of \( 5000 \). 6. **Conclusion:** - The value of \( d \) is \( 5000 \). ### Final Answer: The value of \( d \) is \( 5000 \).
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