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Find the HCF of 513, 1134 and 1215...

Find the HCF of 513, 1134 and 1215

A

27

B

9

C

18

D

54

Text Solution

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The correct Answer is:
To find the HCF (Highest Common Factor) of the numbers 513, 1134, and 1215, we will use the prime factorization method. Here’s a step-by-step solution: ### Step 1: Prime Factorization of Each Number **1. Factorizing 513:** - Divide by 3: \( 513 \div 3 = 171 \) - Divide by 3 again: \( 171 \div 3 = 57 \) - Divide by 3 again: \( 57 \div 3 = 19 \) - 19 is a prime number. - Therefore, the prime factorization of 513 is: \[ 513 = 3^3 \times 19 \] **2. Factorizing 1134:** - Divide by 2: \( 1134 \div 2 = 567 \) - Divide by 3: \( 567 \div 3 = 189 \) - Divide by 3 again: \( 189 \div 3 = 63 \) - Divide by 3 again: \( 63 \div 3 = 21 \) - Divide by 3 again: \( 21 \div 3 = 7 \) - 7 is a prime number. - Therefore, the prime factorization of 1134 is: \[ 1134 = 2^1 \times 3^4 \times 7^1 \] **3. Factorizing 1215:** - Divide by 3: \( 1215 \div 3 = 405 \) - Divide by 3 again: \( 405 \div 3 = 135 \) - Divide by 3 again: \( 135 \div 3 = 45 \) - Divide by 3 again: \( 45 \div 3 = 15 \) - Divide by 3 again: \( 15 \div 3 = 5 \) - 5 is a prime number. - Therefore, the prime factorization of 1215 is: \[ 1215 = 3^5 \times 5^1 \] ### Step 2: Identify Common Factors Now we will identify the common factors from the prime factorizations: - **513:** \( 3^3 \times 19 \) - **1134:** \( 2^1 \times 3^4 \times 7^1 \) - **1215:** \( 3^5 \times 5^1 \) The only common prime factor among all three numbers is \( 3 \). ### Step 3: Determine the Lowest Power of Common Factors The lowest power of the common factor \( 3 \) is: - From 513: \( 3^3 \) - From 1134: \( 3^4 \) - From 1215: \( 3^5 \) The lowest power is \( 3^3 \). ### Step 4: Calculate the HCF Now we calculate the HCF: \[ \text{HCF} = 3^3 = 27 \] ### Conclusion Thus, the HCF of 513, 1134, and 1215 is **27**. ---
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