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The square root of (0.342 xx 0.684)/(0.0...

The square root of `(0.342 xx 0.684)/(0.000342 xx 0.000171)` is :

A

250

B

2500

C

2000

D

4000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(\sqrt{\frac{0.342 \times 0.684}{0.000342 \times 0.000171}}\), we will simplify the terms step by step. ### Step 1: Rewrite the numbers in scientific notation First, we convert the decimal numbers into scientific notation for easier manipulation. - \(0.342 = 3.42 \times 10^{-1}\) - \(0.684 = 6.84 \times 10^{-1}\) - \(0.000342 = 3.42 \times 10^{-4}\) - \(0.000171 = 1.71 \times 10^{-4}\) ### Step 2: Substitute the scientific notation into the expression Now, we substitute these values into the expression: \[ \sqrt{\frac{(3.42 \times 10^{-1}) \times (6.84 \times 10^{-1})}{(3.42 \times 10^{-4}) \times (1.71 \times 10^{-4})}} \] ### Step 3: Simplify the numerator and the denominator Now, we simplify the numerator and the denominator separately. **Numerator:** \[ 3.42 \times 6.84 = 23.328 \] \[ 10^{-1} \times 10^{-1} = 10^{-2} \] So, the numerator becomes: \[ 23.328 \times 10^{-2} \] **Denominator:** \[ 3.42 \times 1.71 = 5.8472 \] \[ 10^{-4} \times 10^{-4} = 10^{-8} \] So, the denominator becomes: \[ 5.8472 \times 10^{-8} \] ### Step 4: Combine the numerator and denominator Now, we can write the entire expression as: \[ \sqrt{\frac{23.328 \times 10^{-2}}{5.8472 \times 10^{-8}}} \] ### Step 5: Simplify the fraction This can be simplified to: \[ \frac{23.328}{5.8472} \times 10^{(-2) - (-8)} = \frac{23.328}{5.8472} \times 10^{6} \] ### Step 6: Calculate the fraction Calculating \( \frac{23.328}{5.8472} \): \[ \frac{23.328}{5.8472} \approx 3.99 \] So, we have: \[ 3.99 \times 10^{6} \] ### Step 7: Take the square root Now, we take the square root of the entire expression: \[ \sqrt{3.99 \times 10^{6}} = \sqrt{3.99} \times \sqrt{10^{6}} = \sqrt{3.99} \times 10^{3} \] Calculating \( \sqrt{3.99} \approx 1.9975 \), we have: \[ 1.9975 \times 10^{3} \approx 1997.5 \] ### Final Answer Thus, the final answer is approximately \(2000\) (rounded). ---
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