Home
Class 14
MATHS
The smallest positive integer, when mult...

The smallest positive integer, when multiplied by 392, the product is a perfect square, is

A

6

B

5

C

3

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To find the smallest positive integer that, when multiplied by 392, results in a perfect square, we can follow these steps: ### Step 1: Prime Factorization of 392 First, we need to find the prime factorization of 392. - Divide 392 by 2: \[ 392 \div 2 = 196 \] - Divide 196 by 2: \[ 196 \div 2 = 98 \] - Divide 98 by 2: \[ 98 \div 2 = 49 \] - Divide 49 by 7: \[ 49 \div 7 = 7 \] - Divide 7 by 7: \[ 7 \div 7 = 1 \] So, the prime factorization of 392 is: \[ 392 = 2^3 \times 7^2 \] ### Step 2: Identify the Exponents Next, we look at the exponents in the prime factorization: - For \(2^3\), the exponent is 3 (which is odd). - For \(7^2\), the exponent is 2 (which is even). ### Step 3: Make Exponents Even To form a perfect square, all exponents in the prime factorization must be even. - The exponent of 2 is 3 (odd), so we need to multiply by \(2^1\) to make it even (3 + 1 = 4). - The exponent of 7 is already even, so we do not need to multiply by anything for 7. ### Step 4: Calculate the Required Integer Thus, the smallest positive integer we need to multiply by 392 to make it a perfect square is: \[ 2^1 = 2 \] ### Final Answer The smallest positive integer that, when multiplied by 392, results in a perfect square is: \[ \boxed{2} \] ---
Promotional Banner

Topper's Solved these Questions

  • SIMPLIFICATION

    KIRAN PUBLICATION|Exercise TYPE-II|43 Videos
  • SIMPLIFICATION

    KIRAN PUBLICATION|Exercise TYPE-III|17 Videos
  • SIMPLE INTERSET

    KIRAN PUBLICATION|Exercise TEST YOURSELF|25 Videos
  • STATISTICS AND DATA INTERPRETATION

    KIRAN PUBLICATION|Exercise TYPE-VIII|8 Videos

Similar Questions

Explore conceptually related problems

Find the smallest number by which 180 must be multiplied so that the product is a perfect square.

The smallest number with which 120 should be multiplied so that the product is a perfect square is

Find the smallest number by which 392 must be multiplied so that the product is a perfect cube.

What is the smallest number by which 392 must be multiplied so that the product is a perfect cube?

What is the smallest number by which 392 must be multiplied so that the product is a perfect cube?

Find the smallest number which when multiplied with 137592 will make the product a perfect cube.Further,find the cube root of the product.

Find the smallest number by 180 which 180 must be multiplied so that the product is a perfect square.

KIRAN PUBLICATION-SIMPLIFICATION-TEST YOURSELF
  1. The smallest positive integer, when multiplied by 392, the product is ...

    Text Solution

    |

  2. Simplify : 1 + (1)/(1 + (2)/(2 + (3)/(1 + (4)/(5))))

    Text Solution

    |

  3. Simplify the following expressions: 2 - 1/(3+1/(4-1/(5+1/(6-1/(7)))...

    Text Solution

    |

  4. Simplify : 7 (1)/(2) - [2 (1)/(4) + {(1)/(4)-(1)/(2) (1 (1)/(2) - (1)/...

    Text Solution

    |

  5. Simplify : 3 div [(8-5) div {(4-2) div (2 + (8)/(13))}] = ?

    Text Solution

    |

  6. Simplify : 5(1)/(2) - [2 (1)/(3) div {(3)/(4) - (1)/(2) ((2)/(3) - bar...

    Text Solution

    |

  7. Simplify : (3.5 xx 1.5)/(0.025 + 0.125 xx 7.5) xx (1)/(3 + (1)/(1 + (1...

    Text Solution

    |

  8. Simplify : (3)/(4 + (5)/(6 + (7)/(8)))-(3)/(5) + (1)/(2) "of 1"(1)/(5)...

    Text Solution

    |

  9. Simplify : 2 div (3)/(17) "of" (2 (3)/(4)+ 3(5)/(8)) + (2)/(5) div 2 (...

    Text Solution

    |

  10. (2.5 xx 3 + 7.5 div 2.5 - "0.5 of 3")/(47 + 12 div 1.5 - "6 of 2" xx 3...

    Text Solution

    |

  11. Simplify : (17)/(7 + (3)/(4 - 2(3)/(4)))xx (2021)/(2193) div (1 (37)/(...

    Text Solution

    |

  12. Simplify : 999 (998)/(999) xx 999 + 999

    Text Solution

    |

  13. Simplify : (8 (3)/(5) + 7 (3)/(4) + 5 (2)/(3) - 4 (1)/(2))/(13 - 11 (9...

    Text Solution

    |

  14. (1 (7)/(9)"of" (27)/(64))/((11)/(12) xx 9 (9)/(11)) div (4 (4)/(7) "of...

    Text Solution

    |

  15. Simplify : 120 + "3 of 5" div [7 xx 2 {10 div 5(24 - 10 xx 2 + bar(7 +...

    Text Solution

    |

  16. Simplify : (1)/(8)"of" ((1)/(10)-(1)/(11))div ((1)/(7) - (1)/(9) div (...

    Text Solution

    |

  17. Simplify : (2(4)/(9) div 3 (2)/(3) "of" (2)/(5) xx (3)/(5) + 1 (1)/(9)...

    Text Solution

    |

  18. Simplify : (5 + 5 xx 5)/(5 xx 5 + 5) xx ((1)/(5) div (1)/(5) "of" (1)/...

    Text Solution

    |

  19. Simplify : ((5)/(6) + (7)/(8)"of" (4)/(5) div (3)/(4) "of" (9)/(10))/(...

    Text Solution

    |

  20. Simplify : ((2)/(3) div (3)/(4)"of" (5)/(6))/((2)/(3) div (3)/(4) xx (...

    Text Solution

    |

  21. If the numerator of a fraction is increased by (1)/(4) and the denomin...

    Text Solution

    |