Home
Class 14
MATHS
The number of perfect square numbers bet...

The number of perfect square numbers between 50 and 1000 is

A

21

B

22

C

23

D

24

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of perfect square numbers between 50 and 1000, we can follow these steps: ### Step 1: Identify the smallest perfect square greater than 50. The smallest integer whose square is greater than 50 is 8, since: \[ 8^2 = 64 \] So, the first perfect square number we consider is 64. ### Step 2: Identify the largest perfect square less than or equal to 1000. The largest integer whose square is less than or equal to 1000 is 31, since: \[ 31^2 = 961 \] So, the largest perfect square number we consider is 961. ### Step 3: List the perfect squares from 8 to 31. The perfect squares from 8 to 31 are: - \( 8^2 = 64 \) - \( 9^2 = 81 \) - \( 10^2 = 100 \) - \( 11^2 = 121 \) - \( 12^2 = 144 \) - \( 13^2 = 169 \) - \( 14^2 = 196 \) - \( 15^2 = 225 \) - \( 16^2 = 256 \) - \( 17^2 = 289 \) - \( 18^2 = 324 \) - \( 19^2 = 361 \) - \( 20^2 = 400 \) - \( 21^2 = 441 \) - \( 22^2 = 484 \) - \( 23^2 = 529 \) - \( 24^2 = 576 \) - \( 25^2 = 625 \) - \( 26^2 = 676 \) - \( 27^2 = 729 \) - \( 28^2 = 784 \) - \( 29^2 = 841 \) - \( 30^2 = 900 \) - \( 31^2 = 961 \) ### Step 4: Count the number of perfect squares. Now, we count the perfect squares from \( 8^2 \) to \( 31^2 \): - The integers from 8 to 31 are: 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31. To find the count: - The total count of integers from 8 to 31 is: \[ 31 - 8 + 1 = 24 \] ### Conclusion: Thus, the number of perfect square numbers between 50 and 1000 is **24**. ---
Promotional Banner

Topper's Solved these Questions

  • SIMPLIFICATION

    KIRAN PUBLICATION|Exercise TYPE-II|43 Videos
  • SIMPLIFICATION

    KIRAN PUBLICATION|Exercise TYPE-III|17 Videos
  • SIMPLE INTERSET

    KIRAN PUBLICATION|Exercise TEST YOURSELF|25 Videos
  • STATISTICS AND DATA INTERPRETATION

    KIRAN PUBLICATION|Exercise TYPE-VIII|8 Videos

Similar Questions

Explore conceptually related problems

There are __________ perfect squares between 1 and 50.

1000 is a perfect square.

There are 2n non-perfect square numbers between two consecutive square numbers n^(2) and (n+1)^(2)

State True or False : There is no square number between 50 and 60.

The number which is not a perfect square is-

There are _________ perfect cubes between 1 and 1000.

The number of numbers that are divisible by 9 between 1and 1000

What least number must be added to 5607 to make the sum a perfect square ? Fnd this perfect square and its square root.

KIRAN PUBLICATION-SIMPLIFICATION-TEST YOURSELF
  1. The number of perfect square numbers between 50 and 1000 is

    Text Solution

    |

  2. Simplify : 1 + (1)/(1 + (2)/(2 + (3)/(1 + (4)/(5))))

    Text Solution

    |

  3. Simplify the following expressions: 2 - 1/(3+1/(4-1/(5+1/(6-1/(7)))...

    Text Solution

    |

  4. Simplify : 7 (1)/(2) - [2 (1)/(4) + {(1)/(4)-(1)/(2) (1 (1)/(2) - (1)/...

    Text Solution

    |

  5. Simplify : 3 div [(8-5) div {(4-2) div (2 + (8)/(13))}] = ?

    Text Solution

    |

  6. Simplify : 5(1)/(2) - [2 (1)/(3) div {(3)/(4) - (1)/(2) ((2)/(3) - bar...

    Text Solution

    |

  7. Simplify : (3.5 xx 1.5)/(0.025 + 0.125 xx 7.5) xx (1)/(3 + (1)/(1 + (1...

    Text Solution

    |

  8. Simplify : (3)/(4 + (5)/(6 + (7)/(8)))-(3)/(5) + (1)/(2) "of 1"(1)/(5)...

    Text Solution

    |

  9. Simplify : 2 div (3)/(17) "of" (2 (3)/(4)+ 3(5)/(8)) + (2)/(5) div 2 (...

    Text Solution

    |

  10. (2.5 xx 3 + 7.5 div 2.5 - "0.5 of 3")/(47 + 12 div 1.5 - "6 of 2" xx 3...

    Text Solution

    |

  11. Simplify : (17)/(7 + (3)/(4 - 2(3)/(4)))xx (2021)/(2193) div (1 (37)/(...

    Text Solution

    |

  12. Simplify : 999 (998)/(999) xx 999 + 999

    Text Solution

    |

  13. Simplify : (8 (3)/(5) + 7 (3)/(4) + 5 (2)/(3) - 4 (1)/(2))/(13 - 11 (9...

    Text Solution

    |

  14. (1 (7)/(9)"of" (27)/(64))/((11)/(12) xx 9 (9)/(11)) div (4 (4)/(7) "of...

    Text Solution

    |

  15. Simplify : 120 + "3 of 5" div [7 xx 2 {10 div 5(24 - 10 xx 2 + bar(7 +...

    Text Solution

    |

  16. Simplify : (1)/(8)"of" ((1)/(10)-(1)/(11))div ((1)/(7) - (1)/(9) div (...

    Text Solution

    |

  17. Simplify : (2(4)/(9) div 3 (2)/(3) "of" (2)/(5) xx (3)/(5) + 1 (1)/(9)...

    Text Solution

    |

  18. Simplify : (5 + 5 xx 5)/(5 xx 5 + 5) xx ((1)/(5) div (1)/(5) "of" (1)/...

    Text Solution

    |

  19. Simplify : ((5)/(6) + (7)/(8)"of" (4)/(5) div (3)/(4) "of" (9)/(10))/(...

    Text Solution

    |

  20. Simplify : ((2)/(3) div (3)/(4)"of" (5)/(6))/((2)/(3) div (3)/(4) xx (...

    Text Solution

    |

  21. If the numerator of a fraction is increased by (1)/(4) and the denomin...

    Text Solution

    |