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For what value of N, 270N will be perfec...

For what value of N, 270N will be perfect square, where 270N is a 4-digit number ?

A

1

B

6

C

4

D

9

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( N \) such that \( 270N \) is a perfect square and a four-digit number, we can follow these steps: ### Step 1: Determine the range of \( N \) Since \( 270N \) is a four-digit number, we need to find the range for \( N \). The smallest four-digit number is 1000, and the largest is 9999. Therefore, we can set up the following inequalities: \[ 1000 \leq 270N \leq 9999 \] ### Step 2: Solve for \( N \) Now, we divide the entire inequality by 270 to isolate \( N \): \[ \frac{1000}{270} \leq N \leq \frac{9999}{270} \] Calculating the values: \[ \frac{1000}{270} \approx 3.70 \quad \text{and} \quad \frac{9999}{270} \approx 37.04 \] Thus, the integer values of \( N \) can range from 4 to 37. ### Step 3: Check for perfect squares Next, we need to check which values of \( N \) make \( 270N \) a perfect square. We can express \( 270 \) in its prime factorization: \[ 270 = 2 \times 3^3 \times 5 \] For \( 270N \) to be a perfect square, all prime factors must have even exponents. The current exponents of the prime factors in \( 270 \) are: - \( 2^1 \) (odd) - \( 3^3 \) (odd) - \( 5^1 \) (odd) To make \( 270N \) a perfect square, \( N \) must provide the necessary factors to make all exponents even. ### Step 4: Determine the necessary factors from \( N \) To make the exponents even: - We need at least one \( 2 \) from \( N \) to make \( 2^1 \) into \( 2^2 \). - We need at least one \( 3 \) from \( N \) to make \( 3^3 \) into \( 3^4 \). - We need at least one \( 5 \) from \( N \) to make \( 5^1 \) into \( 5^2 \). Thus, \( N \) must be at least \( 2 \times 3 \times 5 = 30 \) to ensure all prime factors have even exponents. ### Step 5: Check values of \( N \) from 30 to 37 Now, we can check the values of \( N \) from 30 to 37 to see which makes \( 270N \) a perfect square. - **For \( N = 30 \)**: \[ 270 \times 30 = 8100 \quad (\text{which is } 90^2) \] - **For \( N = 31 \)**: \[ 270 \times 31 = 8370 \quad (\text{not a perfect square}) \] - **For \( N = 32 \)**: \[ 270 \times 32 = 8640 \quad (\text{not a perfect square}) \] - **For \( N = 33 \)**: \[ 270 \times 33 = 8910 \quad (\text{not a perfect square}) \] - **For \( N = 34 \)**: \[ 270 \times 34 = 9180 \quad (\text{not a perfect square}) \] - **For \( N = 35 \)**: \[ 270 \times 35 = 9450 \quad (\text{not a perfect square}) \] - **For \( N = 36 \)**: \[ 270 \times 36 = 9720 \quad (\text{not a perfect square}) \] - **For \( N = 37 \)**: \[ 270 \times 37 = 9990 \quad (\text{not a perfect square}) \] ### Conclusion The only value of \( N \) that makes \( 270N \) a perfect square and a four-digit number is: \[ \boxed{30} \]
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