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Which of the following statements (s) is...

Which of the following statements (s) is/are TRUE ?
I. `11 (1)/(2) + 17 (3)/(4) - 5 (1)/(5) - 2 (1)/(10) = (439)/(20)`
II. `(9)/(1078) gt (11)/(1127) gt (12)/(1219)`
III. `(149)/(151) gt (153)/(155) gt (157)/(159)`

A

Only I

B

Only II

C

Only III

D

None is true

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the statements is true, we will analyze each statement step by step. ### Statement I: **Check: \( 11 \frac{1}{2} + 17 \frac{3}{4} - 5 \frac{1}{5} - 2 \frac{1}{10} = \frac{439}{20} \)** 1. Convert mixed fractions to improper fractions: - \( 11 \frac{1}{2} = 11 + \frac{1}{2} = \frac{22}{2} + \frac{1}{2} = \frac{23}{2} \) - \( 17 \frac{3}{4} = 17 + \frac{3}{4} = \frac{68}{4} + \frac{3}{4} = \frac{71}{4} \) - \( 5 \frac{1}{5} = 5 + \frac{1}{5} = \frac{25}{5} + \frac{1}{5} = \frac{26}{5} \) - \( 2 \frac{1}{10} = 2 + \frac{1}{10} = \frac{20}{10} + \frac{1}{10} = \frac{21}{10} \) 2. Combine the fractions: \[ \frac{23}{2} + \frac{71}{4} - \frac{26}{5} - \frac{21}{10} \] 3. Find the least common multiple (LCM) of the denominators (2, 4, 5, 10), which is 20. 4. Convert each fraction to have a denominator of 20: - \( \frac{23}{2} = \frac{23 \times 10}{2 \times 10} = \frac{230}{20} \) - \( \frac{71}{4} = \frac{71 \times 5}{4 \times 5} = \frac{355}{20} \) - \( \frac{26}{5} = \frac{26 \times 4}{5 \times 4} = \frac{104}{20} \) - \( \frac{21}{10} = \frac{21 \times 2}{10 \times 2} = \frac{42}{20} \) 5. Substitute back into the equation: \[ \frac{230}{20} + \frac{355}{20} - \frac{104}{20} - \frac{42}{20} \] 6. Combine the fractions: \[ \frac{230 + 355 - 104 - 42}{20} = \frac{439}{20} \] **Conclusion for Statement I:** True --- ### Statement II: **Check: \( \frac{9}{1078} > \frac{11}{1127} > \frac{12}{1219} \)** 1. To compare the fractions, cross-multiply: - For \( \frac{9}{1078} \) and \( \frac{11}{1127} \): \[ 9 \times 1127 \quad \text{and} \quad 11 \times 1078 \] Calculate: - \( 9 \times 1127 = 10143 \) - \( 11 \times 1078 = 11858 \) Since \( 10143 < 11858 \), \( \frac{9}{1078} < \frac{11}{1127} \). 2. Now compare \( \frac{11}{1127} \) and \( \frac{12}{1219} \): - Cross-multiply: \[ 11 \times 1219 \quad \text{and} \quad 12 \times 1127 \] Calculate: - \( 11 \times 1219 = 13409 \) - \( 12 \times 1127 = 13524 \) Since \( 13409 < 13524 \), \( \frac{11}{1127} < \frac{12}{1219} \). **Conclusion for Statement II:** False --- ### Statement III: **Check: \( \frac{149}{151} > \frac{153}{155} > \frac{157}{159} \)** 1. Compare \( \frac{149}{151} \) and \( \frac{153}{155} \): - Cross-multiply: \[ 149 \times 155 \quad \text{and} \quad 151 \times 153 \] Calculate: - \( 149 \times 155 = 23095 \) - \( 151 \times 153 = 23103 \) Since \( 23095 < 23103 \), \( \frac{149}{151} < \frac{153}{155} \). 2. Now compare \( \frac{153}{155} \) and \( \frac{157}{159} \): - Cross-multiply: \[ 153 \times 159 \quad \text{and} \quad 155 \times 157 \] Calculate: - \( 153 \times 159 = 24387 \) - \( 155 \times 157 = 24385 \) Since \( 24387 > 24385 \), \( \frac{153}{155} > \frac{157}{159} \). **Conclusion for Statement III:** False --- ### Final Conclusion: - Statement I is **True**. - Statement II is **False**. - Statement III is **False**.
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