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(675 xx 675 xx 675 + 325 xx 325 xx 325)/...

`(675 xx 675 xx 675 + 325 xx 325 xx 325)/(67.5 xx 67.5 + 32.5 xx 32.5 - 67.5 xx 32.5)` is equal to :

A

100

B

10000

C

1000

D

100000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((675 \times 675 \times 675 + 325 \times 325 \times 325)/(67.5 \times 67.5 + 32.5 \times 32.5 - 67.5 \times 32.5)\), we can follow these steps: ### Step 1: Recognize the cubes in the numerator The numerator can be rewritten as: \[ 675^3 + 325^3 \] ### Step 2: Recognize the identity for cubes We can use the algebraic identity: \[ A^3 + B^3 = (A + B)(A^2 - AB + B^2) \] Here, let \(A = 675\) and \(B = 325\). Thus: \[ 675^3 + 325^3 = (675 + 325)(675^2 - 675 \times 325 + 325^2) \] ### Step 3: Calculate \(A + B\) Calculating \(675 + 325\): \[ 675 + 325 = 1000 \] ### Step 4: Calculate \(A^2 - AB + B^2\) Now we need to calculate \(675^2 - 675 \times 325 + 325^2\): - Calculate \(675^2\): \[ 675^2 = 455625 \] - Calculate \(325^2\): \[ 325^2 = 105625 \] - Calculate \(675 \times 325\): \[ 675 \times 325 = 219375 \] Now substituting these values: \[ 675^2 - 675 \times 325 + 325^2 = 455625 - 219375 + 105625 \] Calculating this gives: \[ 455625 - 219375 + 105625 = 341875 \] ### Step 5: Substitute back into the numerator So, the numerator becomes: \[ 1000 \times 341875 \] ### Step 6: Simplify the denominator Now, let's simplify the denominator: \[ 67.5^2 + 32.5^2 - 67.5 \times 32.5 \] Calculating each term: - Calculate \(67.5^2\): \[ 67.5^2 = 4556.25 \] - Calculate \(32.5^2\): \[ 32.5^2 = 1056.25 \] - Calculate \(67.5 \times 32.5\): \[ 67.5 \times 32.5 = 2193.75 \] Now substituting these values: \[ 67.5^2 + 32.5^2 - 67.5 \times 32.5 = 4556.25 + 1056.25 - 2193.75 \] Calculating this gives: \[ 4556.25 + 1056.25 - 2193.75 = 3419.75 \] ### Step 7: Final expression Now we can write the entire expression: \[ \frac{1000 \times 341875}{3419.75} \] ### Step 8: Simplify the fraction To simplify: \[ \frac{1000 \times 341875}{3419.75} = \frac{341875000}{3419.75} \] Calculating this gives: \[ 100000 \] ### Conclusion Thus, the final answer is: \[ \boxed{100000} \]
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