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which one of the following is the least ?
`sqrt(3),root3(2),sqrt(2)` and `root3(4)`

A

`sqrt(2)`

B

`root3(4)`

C

`sqrt(3)`

D

`root3(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find which of the following numbers is the least among \( \sqrt{3}, \sqrt[3]{2}, \sqrt{2}, \text{ and } \sqrt[3]{4} \), we can compare them by expressing each in terms of a common exponent. ### Step 1: Rewrite each expression with fractional exponents - \( \sqrt{3} = 3^{1/2} \) - \( \sqrt[3]{2} = 2^{1/3} \) - \( \sqrt{2} = 2^{1/2} \) - \( \sqrt[3]{4} = 4^{1/3} = (2^2)^{1/3} = 2^{2/3} \) ### Step 2: Find a common denominator for the exponents The exponents we have are \( \frac{1}{2}, \frac{1}{3}, \frac{1}{2}, \text{ and } \frac{2}{3} \). The least common multiple (LCM) of the denominators (2 and 3) is 6. ### Step 3: Convert each expression to have the same denominator - For \( \sqrt{3} = 3^{1/2} \): \[ 3^{1/2} = 3^{3/6} \] - For \( \sqrt[3]{2} = 2^{1/3} \): \[ 2^{1/3} = 2^{2/6} \] - For \( \sqrt{2} = 2^{1/2} \): \[ 2^{1/2} = 2^{3/6} \] - For \( \sqrt[3]{4} = 2^{2/3} \): \[ 2^{2/3} = 2^{4/6} \] ### Step 4: Compare the bases raised to the same power Now we can compare: - \( 3^{3/6} \) - \( 2^{2/6} \) - \( 2^{3/6} \) - \( 2^{4/6} \) ### Step 5: Calculate the values Now we can evaluate the bases raised to the power \( \frac{1}{6} \): 1. \( 3^{3/6} = 3^{0.5} = \sqrt{3} \approx 1.732 \) 2. \( 2^{2/6} = 2^{0.333} \approx 1.260 \) 3. \( 2^{3/6} = 2^{0.5} = \sqrt{2} \approx 1.414 \) 4. \( 2^{4/6} = 2^{0.667} \approx 1.587 \) ### Step 6: Identify the least value From the approximations: - \( \sqrt{3} \approx 1.732 \) - \( \sqrt[3]{2} \approx 1.260 \) - \( \sqrt{2} \approx 1.414 \) - \( \sqrt[3]{4} \approx 1.587 \) The least value is \( \sqrt[3]{2} \). ### Conclusion Thus, the least among \( \sqrt{3}, \sqrt[3]{2}, \sqrt{2}, \text{ and } \sqrt[3]{4} \) is \( \sqrt[3]{2} \). ---
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