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Among sqrt(2), root3(3), root4(5), root3...

Among `sqrt(2)`, `root3(3)`, `root4(5)`, `root3(2)` which one is the greatest ?

A

`root4(5)`

B

`sqrt(2)`

C

`root3(3)`

D

`root3(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which among \( \sqrt{2} \), \( \sqrt[3]{3} \), \( \sqrt[4]{5} \), and \( \sqrt[3]{2} \) is the greatest, we can express each of these roots in terms of powers of their bases. ### Step-by-Step Solution: 1. **Express each root in exponent form**: - \( \sqrt{2} = 2^{1/2} \) - \( \sqrt[3]{3} = 3^{1/3} \) - \( \sqrt[4]{5} = 5^{1/4} \) - \( \sqrt[3]{2} = 2^{1/3} \) 2. **Identify the denominators of the exponents**: - The denominators are 2, 3, 4, and 3. To compare these numbers, we need a common denominator. The least common multiple (LCM) of 2, 3, and 4 is 12. 3. **Convert each exponent to have the common denominator**: - Multiply the exponent of each expression by the LCM (12): - \( \sqrt{2} = 2^{1/2} = 2^{6/12} \) - \( \sqrt[3]{3} = 3^{1/3} = 3^{4/12} \) - \( \sqrt[4]{5} = 5^{1/4} = 5^{3/12} \) - \( \sqrt[3]{2} = 2^{1/3} = 2^{4/12} \) 4. **Now we can compare the values**: - We have: - \( 2^{6/12} = 2^{0.5} \) - \( 3^{4/12} = 3^{0.3333} \) - \( 5^{3/12} = 5^{0.25} \) - \( 2^{4/12} = 2^{0.3333} \) 5. **Calculate the values**: - \( 2^{6/12} = 2^{0.5} = \sqrt{2} \approx 1.414 \) - \( 3^{4/12} = 3^{0.3333} \approx 1.442 \) - \( 5^{3/12} = 5^{0.25} \approx 1.495 \) - \( 2^{4/12} = 2^{0.3333} \approx 1.260 \) 6. **Identify the greatest value**: - Comparing the approximate values: - \( \sqrt{2} \approx 1.414 \) - \( \sqrt[3]{3} \approx 1.442 \) - \( \sqrt[4]{5} \approx 1.495 \) - \( \sqrt[3]{2} \approx 1.260 \) - The greatest value is \( \sqrt[4]{5} \). ### Conclusion: The greatest among \( \sqrt{2} \), \( \sqrt[3]{3} \), \( \sqrt[4]{5} \), and \( \sqrt[3]{2} \) is \( \sqrt[4]{5} \).
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