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Which value among the root3(8), root2(4)...

Which value among the `root3(8)`, `root2(4)`, `root6(64)` is greatest ?

A

`root3(8)`

B

`root2(4)`

C

`root6(64)`

D

All are equal

Text Solution

AI Generated Solution

The correct Answer is:
To determine which value among \( \sqrt[3]{8} \), \( \sqrt{4} \), and \( \sqrt[6]{64} \) is greatest, we can express each root as a power of its base and then compare them. ### Step-by-Step Solution: 1. **Convert each root to exponent form**: - \( \sqrt[3]{8} = 8^{\frac{1}{3}} \) - \( \sqrt{4} = 4^{\frac{1}{2}} \) - \( \sqrt[6]{64} = 64^{\frac{1}{6}} \) 2. **Rewrite the bases as powers of 2**: - \( 8 = 2^3 \), so \( 8^{\frac{1}{3}} = (2^3)^{\frac{1}{3}} = 2^{3 \cdot \frac{1}{3}} = 2^1 = 2 \) - \( 4 = 2^2 \), so \( 4^{\frac{1}{2}} = (2^2)^{\frac{1}{2}} = 2^{2 \cdot \frac{1}{2}} = 2^1 = 2 \) - \( 64 = 2^6 \), so \( 64^{\frac{1}{6}} = (2^6)^{\frac{1}{6}} = 2^{6 \cdot \frac{1}{6}} = 2^1 = 2 \) 3. **Compare the values**: - From our calculations, we have: - \( \sqrt[3]{8} = 2 \) - \( \sqrt{4} = 2 \) - \( \sqrt[6]{64} = 2 \) 4. **Conclusion**: - All three values are equal to 2. ### Final Answer: Thus, the greatest value among \( \sqrt[3]{8} \), \( \sqrt{4} \), and \( \sqrt[6]{64} \) is that they are all equal. ---
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