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The average of n numbers x(1), x(2), ……....

The average of n numbers `x_(1), x_(2), ……. X_(n)` is `bar(x)`. Then the value of `sum_(i=1)^(n) (x_(1) - bar(x))` is equal to

A

n

B

0

C

`nbarx`

D

`barx`

Text Solution

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The correct Answer is:
B
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