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The mean of marks secured by 50 students...

The mean of marks secured by 50 students in division A of class X is 61, 25 students of division B is 57 and that of 50 students of division C is 55. What will be the mean of marks of the students of three divisions of Class X?

A

57.1

B

56.4

C

59.2

D

57.8

Text Solution

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The correct Answer is:
To find the mean of marks of the students from three divisions of Class X, we can follow these steps: ### Step 1: Calculate the total marks for each division. - **Division A**: The mean marks are 61 and there are 50 students. \[ \text{Total Marks for Division A} = \text{Number of Students} \times \text{Mean} = 50 \times 61 = 3050 \] - **Division B**: The mean marks are 57 and there are 25 students. \[ \text{Total Marks for Division B} = 25 \times 57 = 1425 \] - **Division C**: The mean marks are 55 and there are 50 students. \[ \text{Total Marks for Division C} = 50 \times 55 = 2750 \] ### Step 2: Calculate the total marks for all divisions combined. \[ \text{Total Marks} = \text{Total Marks for Division A} + \text{Total Marks for Division B} + \text{Total Marks for Division C} \] \[ \text{Total Marks} = 3050 + 1425 + 2750 = 7225 \] ### Step 3: Calculate the total number of students. \[ \text{Total Students} = \text{Number of Students in Division A} + \text{Number of Students in Division B} + \text{Number of Students in Division C} \] \[ \text{Total Students} = 50 + 25 + 50 = 125 \] ### Step 4: Calculate the mean marks for all students. \[ \text{Mean} = \frac{\text{Total Marks}}{\text{Total Students}} = \frac{7225}{125} \] \[ \text{Mean} = 57.8 \] Thus, the mean of marks of the students of the three divisions of Class X is **57.8**.
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