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The average of first nine prime numbers ...

The average of first nine prime numbers is:

A

9

B

11

C

`11 (2/9)`

D

`11(1/9)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average of the first nine prime numbers, we will follow these steps: ### Step 1: Identify the first nine prime numbers. The first nine prime numbers are: 1. 2 2. 3 3. 5 4. 7 5. 11 6. 13 7. 17 8. 19 9. 23 ### Step 2: Calculate the sum of these prime numbers. Now, let's add these numbers together: - 2 + 3 = 5 - 5 + 5 = 10 - 10 + 7 = 17 - 17 + 11 = 28 - 28 + 13 = 41 - 41 + 17 = 58 - 58 + 19 = 77 - 77 + 23 = 100 So, the sum of the first nine prime numbers is **100**. ### Step 3: Determine the number of observations. The number of observations (prime numbers) we have is **9**. ### Step 4: Calculate the average. The average is calculated by dividing the sum by the number of observations: \[ \text{Average} = \frac{\text{Sum}}{\text{Number of Observations}} = \frac{100}{9} \] ### Step 5: Simplify the average. When we divide 100 by 9, we get: - 100 ÷ 9 = 11 with a remainder of 1, which can be expressed as: \[ 11 \frac{1}{9} \] Thus, the average of the first nine prime numbers is **11 1/9**. ### Final Answer: The average of the first nine prime numbers is **11 1/9**. ---
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