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Three numbers are such that the average ...

Three numbers are such that the average of first two numbers is 2, the average of the last two numbers is 3 and the average of the first and the last numbers is 4, then the average of three numbers is equal to:

A

2

B

3.5

C

3

D

2.5

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The correct Answer is:
To solve the problem step by step, we will denote the three numbers as \( a \), \( b \), and \( c \). ### Step 1: Set up the equations based on the averages given. 1. The average of the first two numbers \( a \) and \( b \) is 2: \[ \frac{a + b}{2} = 2 \] Multiplying both sides by 2 gives: \[ a + b = 4 \quad \text{(Equation 1)} \] 2. The average of the last two numbers \( b \) and \( c \) is 3: \[ \frac{b + c}{2} = 3 \] Multiplying both sides by 2 gives: \[ b + c = 6 \quad \text{(Equation 2)} \] 3. The average of the first and last numbers \( a \) and \( c \) is 4: \[ \frac{a + c}{2} = 4 \] Multiplying both sides by 2 gives: \[ a + c = 8 \quad \text{(Equation 3)} \] ### Step 2: Solve the system of equations. Now we have a system of three equations: 1. \( a + b = 4 \) (Equation 1) 2. \( b + c = 6 \) (Equation 2) 3. \( a + c = 8 \) (Equation 3) We can solve these equations step by step. ### Step 3: Express \( c \) in terms of \( a \) using Equation 3. From Equation 3: \[ c = 8 - a \quad \text{(Equation 4)} \] ### Step 4: Substitute \( c \) into Equation 2. Substituting Equation 4 into Equation 2: \[ b + (8 - a) = 6 \] Simplifying this gives: \[ b + 8 - a = 6 \] \[ b - a = -2 \] Thus, we can express \( b \) in terms of \( a \): \[ b = a - 2 \quad \text{(Equation 5)} \] ### Step 5: Substitute \( b \) into Equation 1. Now, substitute Equation 5 into Equation 1: \[ a + (a - 2) = 4 \] Simplifying this gives: \[ 2a - 2 = 4 \] \[ 2a = 6 \] \[ a = 3 \] ### Step 6: Find \( b \) and \( c \). Using \( a = 3 \) in Equation 5: \[ b = 3 - 2 = 1 \] Using \( a = 3 \) in Equation 4: \[ c = 8 - 3 = 5 \] ### Step 7: Calculate the average of the three numbers. Now we have: - \( a = 3 \) - \( b = 1 \) - \( c = 5 \) The sum of the three numbers is: \[ a + b + c = 3 + 1 + 5 = 9 \] The average of the three numbers is: \[ \text{Average} = \frac{a + b + c}{3} = \frac{9}{3} = 3 \] ### Final Answer: The average of the three numbers is \( 3 \). ---
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