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A batsman scores 98 runs In the 17th mat...

A batsman scores 98 runs In the 17th match of his career. His average runs per match increased by 2.5. What is his average before the 17th match?

A

58

B

60.5

C

63

D

55.5

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the average runs scored by the batsman before the 17th match. Let's break down the solution step by step. ### Step-by-Step Solution: 1. **Define Variables:** Let the average runs scored by the batsman before the 17th match be \( x \). 2. **Calculate Total Runs Before the 17th Match:** Since the batsman played 16 matches before the 17th match, the total runs scored in those 16 matches would be: \[ \text{Total Runs} = 16x \] 3. **Add Runs Scored in the 17th Match:** In the 17th match, the batsman scored 98 runs. Therefore, the total runs after the 17th match would be: \[ \text{Total Runs After 17 Matches} = 16x + 98 \] 4. **Calculate New Average After 17 Matches:** The average after 17 matches can be calculated as: \[ \text{New Average} = \frac{16x + 98}{17} \] 5. **Set Up the Equation:** According to the problem, the new average is 2.5 runs more than the previous average \( x \). Therefore, we can set up the equation: \[ \frac{16x + 98}{17} = x + 2.5 \] 6. **Eliminate the Fraction:** To eliminate the fraction, multiply both sides of the equation by 17: \[ 16x + 98 = 17(x + 2.5) \] 7. **Distribute on the Right Side:** Expanding the right side gives: \[ 16x + 98 = 17x + 42.5 \] 8. **Rearrange the Equation:** Now, let's rearrange the equation to isolate \( x \): \[ 16x + 98 - 42.5 = 17x \] \[ 55.5 = 17x - 16x \] \[ 55.5 = x \] 9. **Conclusion:** Thus, the average runs scored by the batsman before the 17th match is: \[ \boxed{55.5} \]
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