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Find the fraction which bears the same r...

Find the fraction which bears the same ratio to `1/27` that `3/7` does to `5/9`

A

`5/9`

B

`1/35`

C

`45/7`

D

`7/45`

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The correct Answer is:
To solve the problem, we need to find a fraction \( x \) such that the ratio of \( x \) to \( \frac{1}{27} \) is the same as the ratio of \( \frac{3}{7} \) to \( \frac{5}{9} \). ### Step-by-Step Solution: 1. **Set Up the Ratios**: We can express the relationship as: \[ \frac{x}{\frac{1}{27}} = \frac{\frac{3}{7}}{\frac{5}{9}} \] 2. **Simplify the Right Side**: To simplify \( \frac{\frac{3}{7}}{\frac{5}{9}} \), we multiply by the reciprocal of the denominator: \[ \frac{3}{7} \times \frac{9}{5} = \frac{3 \times 9}{7 \times 5} = \frac{27}{35} \] 3. **Substitute Back into the Equation**: Now our equation looks like this: \[ \frac{x}{\frac{1}{27}} = \frac{27}{35} \] 4. **Cross Multiply**: To eliminate the fraction on the left side, we cross multiply: \[ x \cdot 35 = \frac{27}{35} \cdot \frac{1}{27} \] This simplifies to: \[ x \cdot 35 = 27 \cdot \frac{1}{27} = 1 \] 5. **Solve for \( x \)**: Now, divide both sides by 35 to isolate \( x \): \[ x = \frac{1}{35} \] ### Final Answer: The fraction which bears the same ratio to \( \frac{1}{27} \) that \( \frac{3}{7} \) does to \( \frac{5}{9} \) is \( \frac{1}{35} \).
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