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The mean proportional between (3+sqrt(2)...

The mean proportional between `(3+sqrt(2))` and `(12 - sqrt(32))` is:

A

`sqrt(7)`

B

`2sqrt(7)`

C

6

D

`(15- 3sqrt(2))/2`

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AI Generated Solution

The correct Answer is:
To find the mean proportional between \( (3 + \sqrt{2}) \) and \( (12 - \sqrt{32}) \), we will follow these steps: ### Step 1: Understand the formula for mean proportional The mean proportional \( m \) between two numbers \( x \) and \( y \) can be calculated using the formula: \[ m = \sqrt{x \cdot y} \] ### Step 2: Identify the values of \( x \) and \( y \) Here, we have: \[ x = 3 + \sqrt{2} \] \[ y = 12 - \sqrt{32} \] ### Step 3: Simplify \( y \) First, we simplify \( \sqrt{32} \): \[ \sqrt{32} = \sqrt{16 \cdot 2} = 4\sqrt{2} \] So, we can rewrite \( y \): \[ y = 12 - 4\sqrt{2} \] ### Step 4: Calculate the product \( x \cdot y \) Now we need to calculate \( x \cdot y \): \[ x \cdot y = (3 + \sqrt{2})(12 - 4\sqrt{2}) \] Using the distributive property (FOIL method): \[ = 3 \cdot 12 + 3 \cdot (-4\sqrt{2}) + \sqrt{2} \cdot 12 + \sqrt{2} \cdot (-4\sqrt{2}) \] \[ = 36 - 12\sqrt{2} + 12\sqrt{2} - 4 \cdot 2 \] \[ = 36 - 8 \] \[ = 28 \] ### Step 5: Find the mean proportional Now, we can find the mean proportional: \[ m = \sqrt{x \cdot y} = \sqrt{28} \] We can simplify \( \sqrt{28} \): \[ \sqrt{28} = \sqrt{4 \cdot 7} = 2\sqrt{7} \] ### Final Answer Thus, the mean proportional between \( (3 + \sqrt{2}) \) and \( (12 - \sqrt{32}) \) is: \[ \boxed{2\sqrt{7}} \]
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KIRAN PUBLICATION-RATIO AND PROPORTION -TYPE-III
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