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If (3/2)x = (5/7)y = (6/5)z, what is x:y...

If `(3/2)x = (5/7)y = (6/5)z`, what is `x:y:z` ?

A

`105: 50 : 84`

B

`24 : 25 : 32`

C

`15 : 21 : 25`

D

`20 : 42 : 25`

Text Solution

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The correct Answer is:
To find the ratio \( x:y:z \) given that \( \frac{3}{2}x = \frac{5}{7}y = \frac{6}{5}z \), we can follow these steps: ### Step 1: Set a common variable Let \( k \) be the common value such that: \[ \frac{3}{2}x = k, \quad \frac{5}{7}y = k, \quad \frac{6}{5}z = k \] ### Step 2: Express \( x \), \( y \), and \( z \) in terms of \( k \) From the first equation: \[ x = \frac{2k}{3} \] From the second equation: \[ y = \frac{7k}{5} \] From the third equation: \[ z = \frac{5k}{6} \] ### Step 3: Find a common denominator To find the ratio \( x:y:z \), we need to express \( x \), \( y \), and \( z \) with a common denominator. The denominators are 3, 5, and 6. The least common multiple (LCM) of these numbers is 30. ### Step 4: Convert each variable to have the common denominator Now we convert each expression to have a denominator of 30: - For \( x \): \[ x = \frac{2k}{3} = \frac{2k \cdot 10}{3 \cdot 10} = \frac{20k}{30} \] - For \( y \): \[ y = \frac{7k}{5} = \frac{7k \cdot 6}{5 \cdot 6} = \frac{42k}{30} \] - For \( z \): \[ z = \frac{5k}{6} = \frac{5k \cdot 5}{6 \cdot 5} = \frac{25k}{30} \] ### Step 5: Write the ratio Now we can write the ratio \( x:y:z \): \[ x:y:z = 20k:42k:25k \] ### Step 6: Simplify the ratio Since \( k \) is common in all terms, we can simplify: \[ x:y:z = 20:42:25 \] ### Step 7: Further simplify if possible To simplify \( 20:42:25 \), we can find the GCD of the numbers: - The GCD of 20 and 42 is 2. - The GCD of 20, 42, and 25 is 1 (since 25 is not divisible by 2). Thus, the simplest form remains: \[ x:y:z = 20:42:25 \] ### Final Answer The ratio \( x:y:z \) is \( 20:42:25 \). ---
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