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Eighteen years ago, the ratio of A's age...

Eighteen years ago, the ratio of A's age to B's age was `8 : 13`. Their present ratios are `5:7`. What is the present age of A ?

A

60 years

B

70 years

C

50 years

D

40 years

Text Solution

AI Generated Solution

The correct Answer is:
To find the present age of A, we can follow these steps: ### Step 1: Set up the equations based on the given ratios. Eighteen years ago, the ratio of A's age to B's age was 8:13. Let's denote A's age 18 years ago as \(8k\) and B's age as \(13k\). ### Step 2: Express their present ages. Since 18 years have passed, we can express their present ages as: - A's present age = \(8k + 18\) - B's present age = \(13k + 18\) ### Step 3: Set up the equation using the current ratio. The current ratio of their ages is given as 5:7. Therefore, we can set up the equation: \[ \frac{8k + 18}{13k + 18} = \frac{5}{7} \] ### Step 4: Cross-multiply to eliminate the fraction. Cross-multiplying gives us: \[ 7(8k + 18) = 5(13k + 18) \] ### Step 5: Expand both sides of the equation. Expanding both sides results in: \[ 56k + 126 = 65k + 90 \] ### Step 6: Rearrange the equation to isolate \(k\). Now, we will move all terms involving \(k\) to one side and constant terms to the other side: \[ 56k - 65k = 90 - 126 \] This simplifies to: \[ -9k = -36 \] ### Step 7: Solve for \(k\). Dividing both sides by -9 gives: \[ k = 4 \] ### Step 8: Calculate A's present age. Now that we have the value of \(k\), we can find A's present age: \[ \text{A's present age} = 8k + 18 = 8(4) + 18 = 32 + 18 = 50 \] ### Final Answer: The present age of A is **50 years**. ---
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KIRAN PUBLICATION-RATIO AND PROPORTION -TYPE-IV
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