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Two alloys are both made up of copper an...

Two alloys are both made up of copper and tin. The ratio of copper and tin in the first alloy is 1:3 and in the second alloy is 2:5. In what ratio should the two alloys be mixed to obtain a new alloy in which the ratio of tin and copper be 8:3?

A

`3:5`

B

`4:7`

C

`3:8`

D

`5:11`

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The correct Answer is:
To solve the problem, we need to determine the ratio in which the two alloys should be mixed to achieve a new alloy with a specific ratio of tin to copper. Let's break down the solution step by step. ### Step 1: Understand the Ratios of the Alloys - **Alloy 1** has a ratio of copper to tin as 1:3. - **Alloy 2** has a ratio of copper to tin as 2:5. From these ratios, we can determine the fraction of copper and tin in each alloy. **Alloy 1:** - Total parts = 1 + 3 = 4 - Copper in Alloy 1 = \( \frac{1}{4} \) - Tin in Alloy 1 = \( \frac{3}{4} \) **Alloy 2:** - Total parts = 2 + 5 = 7 - Copper in Alloy 2 = \( \frac{2}{7} \) - Tin in Alloy 2 = \( \frac{5}{7} \) ### Step 2: Set Up the Desired Ratio We want to mix these two alloys to create a new alloy with a ratio of tin to copper as 8:3. This means: - Total parts = 8 + 3 = 11 - Fraction of tin = \( \frac{8}{11} \) - Fraction of copper = \( \frac{3}{11} \) ### Step 3: Use Alligation to Find the Mixing Ratio We can use the alligation method to find the ratio in which the two alloys should be mixed. 1. **Calculate the effective fractions:** - Fraction of tin in Alloy 1 = \( \frac{3}{4} \) - Fraction of copper in Alloy 1 = \( \frac{1}{4} \) - Fraction of tin in Alloy 2 = \( \frac{5}{7} \) - Fraction of copper in Alloy 2 = \( \frac{2}{7} \) 2. **Calculate the required fractions:** - Required fraction of tin = \( \frac{8}{11} \) - Required fraction of copper = \( \frac{3}{11} \) 3. **Set up the alligation:** - For Alloy 1: - Tin: \( \frac{3}{4} \) - \( \frac{8}{11} \) - Copper: \( \frac{1}{4} \) - \( \frac{3}{11} \) - For Alloy 2: - Tin: \( \frac{5}{7} \) - \( \frac{8}{11} \) - Copper: \( \frac{2}{7} \) - \( \frac{3}{11} \) 4. **Calculate the differences:** - For Alloy 1 (Tin): \[ \frac{3}{4} - \frac{8}{11} = \frac{33 - 32}{44} = \frac{1}{44} \] - For Alloy 2 (Copper): \[ \frac{5}{7} - \frac{8}{11} = \frac{55 - 56}{77} = -\frac{1}{77} \] ### Step 4: Find the Mixing Ratio The ratio of the two alloys is given by the inverses of the differences calculated: \[ \text{Ratio} = \frac{\frac{1}{44}}{-\frac{1}{77}} = \frac{77}{44} = \frac{7}{4} \] ### Final Answer The two alloys should be mixed in the ratio of **7:4**. ---
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