The ratio of milk and water in mixtures of four containers are 5:3, 2:1, 3:2 and 7:4 re spectively. In which container is the quantity of milk, relative to water, minimum?

Options

A. first
B. second
C. third
D. fourth

Answer

To determine in which container the quantity of milk relative to water is minimum, we will calculate the percentage of milk in each container based on the given ratios.

### Step-by-Step Solution:

1. **Identify the Ratios**:
- Container 1: Milk:Water = 5:3
- Container 2: Milk:Water = 2:1
- Container 3: Milk:Water = 3:2
- Container 4: Milk:Water = 7:4

2. **Calculate the Total Parts for Each Ratio**:
- Container 1: 5 + 3 = 8 parts
- Container 2: 2 + 1 = 3 parts
- Container 3: 3 + 2 = 5 parts
- Container 4: 7 + 4 = 11 parts

3. **Calculate the Percentage of Milk in Each Container**:
- Container 1:
\[ \text{Percentage of Milk} = \left(\frac{5}{8}\right) \times 100 = 62.5\% \]
- Container 2:
\[ \text{Percentage of Milk} = \left(\frac{2}{3}\right) \times 100 \approx 66.67\% \]
- Container 3:
\[ \text{Percentage of Milk} = \left(\frac{3}{5}\right) \times 100 = 60\% \]
- Container 4:
\[ \text{Percentage of Milk} = \left(\frac{7}{11}\right) \times 100 \approx 63.64\% \]

4. **Compare the Percentages**:
- Container 1: 62.5%
- Container 2: 66.67%
- Container 3: 60%
- Container 4: 63.64%

5. **Determine the Minimum Percentage**:
- The minimum percentage of milk relative to water is in Container 3, which is 60%.

### Conclusion:
The container in which the quantity of milk relative to water is minimum is **Container 3**.