Rahul adds 2 litres of alcohol in 8 litres of water and Dinesh adds 1 litre of alcohol in 9 litres of water. What is the ratio of the percentage of alcohol in the two mixturers?

Options

A. `7:4`
B. `2:1`
C. `5:2`
D. `8:3`

Answer

To solve the problem, we need to find the percentage of alcohol in the mixtures prepared by Rahul and Dinesh, and then determine the ratio of these percentages.

### Step 1: Calculate the percentage of alcohol in Rahul's mixture.

Rahul adds 2 liters of alcohol to 8 liters of water.

**Total volume of Rahul's mixture = Volume of alcohol + Volume of water**
= 2 liters + 8 liters = 10 liters

**Percentage of alcohol in Rahul's mixture = (Volume of alcohol / Total volume) × 100**
= (2 liters / 10 liters) × 100
= 20%

### Step 2: Calculate the percentage of alcohol in Dinesh's mixture.

Dinesh adds 1 liter of alcohol to 9 liters of water.

**Total volume of Dinesh's mixture = Volume of alcohol + Volume of water**
= 1 liter + 9 liters = 10 liters

**Percentage of alcohol in Dinesh's mixture = (Volume of alcohol / Total volume) × 100**
= (1 liter / 10 liters) × 100
= 10%

### Step 3: Find the ratio of the percentages of alcohol in the two mixtures.

**Ratio of percentages = Percentage of alcohol in Rahul's mixture : Percentage of alcohol in Dinesh's mixture**
= 20% : 10%

To simplify the ratio, we can divide both sides by 10:

= 2 : 1

### Final Answer:
The ratio of the percentage of alcohol in the two mixtures is **2 : 1**.

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