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Two numbers are 40% and 80% less than a ...

Two numbers are 40% and 80% less than a third number. By how much percent is the second number to be enhanced to make it equal to the first number?

A

100

B

33.3

C

66.6

D

200

Text Solution

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The correct Answer is:
To solve the problem step by step, let's define the numbers clearly and calculate the required percentage increase. **Step 1: Define the third number.** Let the third number be \( x \). **Step 2: Calculate the first number.** The first number is 40% less than the third number: \[ \text{First number} = x - 0.4x = 0.6x \] **Step 3: Calculate the second number.** The second number is 80% less than the third number: \[ \text{Second number} = x - 0.8x = 0.2x \] **Step 4: Determine the difference between the first and second numbers.** To find out how much the second number needs to be enhanced to equal the first number, we calculate the difference: \[ \text{Difference} = \text{First number} - \text{Second number} = 0.6x - 0.2x = 0.4x \] **Step 5: Calculate the percentage increase needed.** To find the percentage increase required to make the second number equal to the first number, we use the formula: \[ \text{Percentage Increase} = \left( \frac{\text{Difference}}{\text{Second number}} \right) \times 100 \] Substituting the values: \[ \text{Percentage Increase} = \left( \frac{0.4x}{0.2x} \right) \times 100 = \left( 2 \right) \times 100 = 200\% \] Thus, the second number needs to be enhanced by **200%** to make it equal to the first number. ---
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