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The numerator of a fraction is in crease...

The numerator of a fraction is in creased by 20% and denomina tor is decreased by 20%. The value of the fraction becomes The original fraction is

A

`3/2`

B

`8/15`

C

`7/11`

D

`4/5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to understand the effect of increasing the numerator by 20% and decreasing the denominator by 20% on the value of the fraction. Let's denote the original fraction as \( \frac{a}{b} \), where \( a \) is the numerator and \( b \) is the denominator. ### Step 1: Increase the Numerator by 20% When we increase the numerator \( a \) by 20%, the new numerator becomes: \[ a' = a + 0.2a = 1.2a \] ### Step 2: Decrease the Denominator by 20% When we decrease the denominator \( b \) by 20%, the new denominator becomes: \[ b' = b - 0.2b = 0.8b \] ### Step 3: Form the New Fraction The new fraction after these changes is: \[ \frac{a'}{b'} = \frac{1.2a}{0.8b} \] ### Step 4: Simplify the New Fraction To simplify \( \frac{1.2a}{0.8b} \): \[ \frac{1.2a}{0.8b} = \frac{1.2}{0.8} \cdot \frac{a}{b} \] Calculating \( \frac{1.2}{0.8} \): \[ \frac{1.2}{0.8} = \frac{12}{8} = \frac{3}{2} \] Thus, the new fraction becomes: \[ \frac{3}{2} \cdot \frac{a}{b} \] ### Step 5: Relate the New Fraction to the Original Fraction According to the problem, the new fraction is equal to \( \frac{3}{2} \) times the original fraction. Therefore, we can set up the equation: \[ \frac{3}{2} \cdot \frac{a}{b} = \frac{a'}{b'} \] This implies that the original fraction \( \frac{a}{b} \) is \( \frac{2}{3} \) of the new fraction. ### Step 6: Conclusion The original fraction \( \frac{a}{b} \) can be expressed as: \[ \frac{a}{b} = \frac{2}{3} \cdot \frac{3}{2} = \frac{2}{3} \] Thus, the original fraction is \( \frac{2}{3} \).
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