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Two numbers are 10% and 25% leaser than ...

Two numbers are `10%` and `25%` leaser than a third number. By how much percent is the second number to be enhanced to make it equal to the first number?

A

16.67 percent.

B

20 percent.

C

15 percent.

D

60 percent.

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The correct Answer is:
To solve the problem step by step, we can follow these steps: ### Step 1: Define the Third Number Let’s assume the third number is \( C = 100 \). ### Step 2: Calculate the First Number The first number \( A \) is 10% less than the third number \( C \). \[ A = C - 10\% \text{ of } C = 100 - 10\% \text{ of } 100 = 100 - 10 = 90 \] ### Step 3: Calculate the Second Number The second number \( B \) is 25% less than the third number \( C \). \[ B = C - 25\% \text{ of } C = 100 - 25\% \text{ of } 100 = 100 - 25 = 75 \] ### Step 4: Find the Difference Between the Two Numbers Now, we need to find the difference between the first number \( A \) and the second number \( B \). \[ \text{Difference} = A - B = 90 - 75 = 15 \] ### Step 5: Calculate the Percentage Increase Required To find out by how much percent the second number \( B \) needs to be enhanced to make it equal to the first number \( A \), we use the formula for percentage increase: \[ \text{Percentage Increase} = \left( \frac{\text{Difference}}{B} \right) \times 100 \] Substituting the values we have: \[ \text{Percentage Increase} = \left( \frac{15}{75} \right) \times 100 = 20\% \] ### Conclusion The second number needs to be enhanced by **20%** to make it equal to the first number. ---
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