In the annual examination. Mahuya got 10% less marks than Supriyo in Mathematics. Mahuya got 81 marks. The marks of Supriyo are

Options

A. A) 90
B. B) 87
C. C) 88
D. D) 89

Answer

To find out the marks of Supriyo based on the information given, we can follow these steps:

### Step 1: Understand the relationship between Mahuya's and Supriyo's marks
Mahuya got 10% less marks than Supriyo. This means if Supriyo's marks are represented as \( S \), then Mahuya's marks can be expressed as:
\[ M = S - 0.1S = 0.9S \]

### Step 2: Substitute the known value
We know that Mahuya got 81 marks. Therefore, we can set up the equation:
\[ 0.9S = 81 \]

### Step 3: Solve for Supriyo's marks
To find Supriyo's marks \( S \), we need to isolate \( S \) in the equation:
\[ S = \frac{81}{0.9} \]

### Step 4: Calculate the value
Now, we perform the calculation:
\[ S = \frac{81}{0.9} = 81 \times \frac{10}{9} = 90 \]

### Conclusion
Thus, the marks of Supriyo are:
\[ S = 90 \]

### Final Answer
Supriyo got **90 marks**.

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