A student scored 32% marks in science subjects out of 300. How much should he score in language papers out of 200 if he is to get overall 46% marks?

Options

A. A) 72%
B. B) 67%
C. C) 66%
D. D) 60%

Answer

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the total marks required for an overall percentage of 46%
The total maximum marks for both subjects (science and language) is:
- Science: 300
- Language: 200
- Total = 300 + 200 = 500

To find out how many marks the student needs to score to achieve 46% overall:
\[ \text{Total marks required} = 46\% \text{ of } 500 = \frac{46}{100} \times 500 = 230 \]

### Step 2: Calculate the marks scored in science
The student scored 32% in science out of 300 marks. To find out how many marks that is:
\[ \text{Marks scored in science} = 32\% \text{ of } 300 = \frac{32}{100} \times 300 = 96 \]

### Step 3: Calculate the marks needed in language papers
To find out how many marks the student needs to score in language papers to reach the total of 230 marks:
\[ \text{Marks needed in language} = \text{Total marks required} - \text{Marks scored in science} \]
\[ \text{Marks needed in language} = 230 - 96 = 134 \]

### Step 4: Calculate the percentage required in language papers
Now, we need to find out what percentage 134 marks is out of the maximum 200 marks in language papers:
\[ \text{Percentage in language} = \left(\frac{\text{Marks needed in language}}{\text{Maximum marks in language}}\right) \times 100 \]
\[ \text{Percentage in language} = \left(\frac{134}{200}\right) \times 100 = 67\% \]

### Final Answer
The student needs to score **67%** in language papers.

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