In an examination A got 25% marks more than B. B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, the marks obtained by A were

Options

A. 405
B. 450
C. 360
D. 400

Answer

To solve the problem step by step, let's analyze the relationships between the marks obtained by A, B, C, and D.

### Step 1: Understand the relationships
1. A got 25% more marks than B.
2. B got 10% less than C.
3. C got 25% more than D.

### Step 2: Assign marks to D
Given that D got 320 marks, we can denote D's marks as:
- D = 320

### Step 3: Calculate C's marks
Since C got 25% more than D, we can calculate C's marks as follows:
- C = D + 25% of D
- C = 320 + (25/100) * 320
- C = 320 + 80
- C = 400

### Step 4: Calculate B's marks
B got 10% less than C, so we can calculate B's marks as:
- B = C - 10% of C
- B = 400 - (10/100) * 400
- B = 400 - 40
- B = 360

### Step 5: Calculate A's marks
A got 25% more than B, so we can calculate A's marks as:
- A = B + 25% of B
- A = 360 + (25/100) * 360
- A = 360 + 90
- A = 450

### Final Answer
The marks obtained by A are **450**.

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