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The population of a village was 9800. In...

The population of a village was 9800. In a year, with the tomase In population of males by 8% and that of females by 5%, the pop ulation of the village became 10458, What was the number of males in the village before in crease?

A

4200

B

4410

C

5600

D

6048

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the number of males in the village before the increase in population. Let's break it down step by step. ### Step 1: Understand the given data - Initial population of the village = 9800 - New population after the increase = 10458 - Increase in the population of males = 8% - Increase in the population of females = 5% ### Step 2: Calculate the total increase in population To find the total increase in population, we subtract the initial population from the new population. \[ \text{Increase in population} = \text{New population} - \text{Initial population} \] \[ \text{Increase in population} = 10458 - 9800 = 658 \] ### Step 3: Define the variables Let: - \( M \) = number of males in the village before the increase - \( F \) = number of females in the village before the increase From the initial population, we have: \[ M + F = 9800 \quad \text{(1)} \] ### Step 4: Calculate the increase in males and females The increase in males and females can be expressed as: - Increase in males = \( 0.08M \) - Increase in females = \( 0.05F \) The total increase in population can also be expressed as the sum of the increases in males and females: \[ 0.08M + 0.05F = 658 \quad \text{(2)} \] ### Step 5: Solve the equations Now we have two equations: 1. \( M + F = 9800 \) 2. \( 0.08M + 0.05F = 658 \) From equation (1), we can express \( F \) in terms of \( M \): \[ F = 9800 - M \quad \text{(3)} \] Substituting equation (3) into equation (2): \[ 0.08M + 0.05(9800 - M) = 658 \] Expanding this: \[ 0.08M + 490 - 0.05M = 658 \] Combining like terms: \[ 0.03M + 490 = 658 \] Subtracting 490 from both sides: \[ 0.03M = 168 \] Dividing by 0.03: \[ M = \frac{168}{0.03} = 5600 \] ### Step 6: Conclusion The number of males in the village before the increase was **5600**. ---
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