A spider climbed 62 `1/2` % of the height of the pole in one hour and in the next hour It covered 12 `1/2`% of the remaining height. If pole's height is 192 m, then dis tance climbed in second hour is

Options

A. 3m
B. 5m
C. 7m
D. 9m

Answer

To solve the problem step by step, we will follow the calculations as described in the video transcript.

### Step 1: Calculate the height climbed in the first hour.
The spider climbed \(62 \frac{1}{2}\% \) of the height of the pole in the first hour.

First, convert \(62 \frac{1}{2}\% \) to a fraction:
\[ 62 \frac{1}{2}\% = \frac{125}{200} = \frac{5}{8} \]

Now, calculate the distance climbed in the first hour:
\[ \text{Height of the pole} = 192 \text{ m} \]
\[ \text{Distance climbed in the first hour} = 192 \times \frac{5}{8} \]
\[ = 192 \times 0.625 = 120 \text{ m} \]

### Step 2: Calculate the remaining height after the first hour.
After climbing 120 m, the remaining height of the pole is:
\[ \text{Remaining height} = 192 - 120 = 72 \text{ m} \]

### Step 3: Calculate the height climbed in the second hour.
In the second hour, the spider climbed \(12 \frac{1}{2}\% \) of the remaining height.

Convert \(12 \frac{1}{2}\% \) to a fraction:
\[ 12 \frac{1}{2}\% = \frac{12.5}{100} = \frac{1}{8} \]

Now, calculate the distance climbed in the second hour:
\[ \text{Distance climbed in the second hour} = 72 \times \frac{1}{8} \]
\[ = 72 \times 0.125 = 9 \text{ m} \]

### Final Answer:
The distance climbed in the second hour is **9 m**.

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