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A man had Rs 16,000, part of which he le...

A man had Rs 16,000, part of which he lent at 4 % and the rest at 5 % per annum simple interset. If the total interset received was Rs 700 in one year, the money lent at 4 % per annum was

A

Rs 12,000

B

Rs 8,000

C

Rs 10,000

D

Rs 6,000

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The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Define the Variables Let \( x \) be the amount of money lent at 4% per annum. Therefore, the amount lent at 5% per annum will be \( 16000 - x \). **Hint:** Identify the total amount and split it into two parts based on the interest rates. ### Step 2: Write the Simple Interest Formula The formula for simple interest is given by: \[ \text{Simple Interest} = \frac{P \times R \times T}{100} \] Where: - \( P \) is the principal amount, - \( R \) is the rate of interest, - \( T \) is the time in years. ### Step 3: Calculate the Interest for Each Part 1. Interest from the amount lent at 4%: \[ \text{Interest at 4%} = \frac{x \times 4 \times 1}{100} = \frac{4x}{100} = 0.04x \] 2. Interest from the amount lent at 5%: \[ \text{Interest at 5%} = \frac{(16000 - x) \times 5 \times 1}{100} = \frac{5(16000 - x)}{100} = 800 - 0.05x \] ### Step 4: Set Up the Equation According to the problem, the total interest received from both parts is Rs 700. Therefore, we can set up the equation: \[ 0.04x + (800 - 0.05x) = 700 \] ### Step 5: Simplify the Equation Combine like terms: \[ 0.04x - 0.05x + 800 = 700 \] \[ -0.01x + 800 = 700 \] ### Step 6: Solve for \( x \) Subtract 800 from both sides: \[ -0.01x = 700 - 800 \] \[ -0.01x = -100 \] Now, divide both sides by -0.01: \[ x = \frac{-100}{-0.01} = 10000 \] ### Step 7: Conclusion The amount of money lent at 4% per annum is Rs 10,000. **Final Answer:** Rs 10,000 ---
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