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In 3 years Rs. 3000 amounts to Rs. 3993 ...

In 3 years `Rs. 3000` amounts to `Rs. 3993` at `x%` compound interest, compounded annually. The value of x is

A

10

B

8

C

`5`

D

`1(1)/3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the formula for compound interest. The formula for the amount \( A \) after \( t \) years at a principal \( P \) with an interest rate \( r \% \) compounded annually is given by: \[ A = P \left(1 + \frac{r}{100}\right)^t \] ### Step 1: Identify the given values - Principal \( P = 3000 \) - Amount \( A = 3993 \) - Time \( t = 3 \) years - Rate \( r = x \% \) (which we need to find) ### Step 2: Substitute the values into the formula We can substitute the known values into the compound interest formula: \[ 3993 = 3000 \left(1 + \frac{x}{100}\right)^3 \] ### Step 3: Divide both sides by 3000 To isolate the term with \( x \), we divide both sides by 3000: \[ \frac{3993}{3000} = \left(1 + \frac{x}{100}\right)^3 \] Calculating the left side: \[ \frac{3993}{3000} = 1.331 \] So we have: \[ 1.331 = \left(1 + \frac{x}{100}\right)^3 \] ### Step 4: Take the cube root of both sides To eliminate the exponent, we take the cube root of both sides: \[ \sqrt[3]{1.331} = 1 + \frac{x}{100} \] Calculating the cube root: \[ \sqrt[3]{1.331} \approx 1.1 \] So we have: \[ 1.1 = 1 + \frac{x}{100} \] ### Step 5: Solve for \( x \) Now, we subtract 1 from both sides: \[ 0.1 = \frac{x}{100} \] Next, multiply both sides by 100 to solve for \( x \): \[ x = 0.1 \times 100 = 10 \] ### Conclusion The value of \( x \) is \( 10\% \). ---
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