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A sum of money becomes 1.331 times in 3 ...

A sum of money becomes 1.331 times in 3 years as compound interest. The rate of interest is

A

`8%`

B

`7.5% `

C

`10% `

D

`50% `

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the concept of compound interest. ### Step 1: Understand the problem We know that a sum of money becomes 1.331 times in 3 years as compound interest. We need to find the rate of interest. ### Step 2: Define the principal amount Let's assume the principal amount (P) is 1000X. This is a convenient choice because it allows us to work with whole numbers. ### Step 3: Calculate the amount after 3 years According to the problem, the amount (A) after 3 years is 1.331 times the principal. Therefore: \[ A = 1.331 \times 1000X = 1331X \] ### Step 4: Use the compound interest formula The formula for the amount in compound interest is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] where: - A = final amount - P = principal amount - r = rate of interest - n = number of years Substituting the values we have: \[ 1331X = 1000X \left(1 + \frac{r}{100}\right)^3 \] ### Step 5: Simplify the equation We can divide both sides by 1000X (assuming X is not zero): \[ \frac{1331X}{1000X} = \left(1 + \frac{r}{100}\right)^3 \] This simplifies to: \[ \frac{1331}{1000} = \left(1 + \frac{r}{100}\right)^3 \] ### Step 6: Calculate the left-hand side Calculating \( \frac{1331}{1000} \): \[ \frac{1331}{1000} = 1.331 \] ### Step 7: Take the cube root To find \( 1 + \frac{r}{100} \), we take the cube root of both sides: \[ 1 + \frac{r}{100} = \sqrt[3]{1.331} \] ### Step 8: Calculate the cube root The cube root of 1.331 is: \[ \sqrt[3]{1.331} = 1.1 \] ### Step 9: Solve for r Now we can solve for \( r \): \[ 1 + \frac{r}{100} = 1.1 \] Subtracting 1 from both sides gives: \[ \frac{r}{100} = 0.1 \] Multiplying both sides by 100: \[ r = 10 \] ### Final Answer The rate of interest is **10%**. ---
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