Home
Class 14
MATHS
Three pipes P, Q and R can separately fi...

Three pipes P, Q and R can separately fill a cistern in 4,8 and 12 hours respectively. Another pipe S can empty the completely filled cistern in 10 hours. Which of the following arrangements will fill the empty cistern in less time than others ?

A

Q alone is open.

B

P and S are open.

C

P, R and S are open.

D

P, Q and S are open.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how long it will take to fill a cistern using different combinations of pipes P, Q, R, and S. ### Given: - Pipe P can fill the cistern in 4 hours. - Pipe Q can fill the cistern in 8 hours. - Pipe R can fill the cistern in 12 hours. - Pipe S can empty the cistern in 10 hours. ### Step 1: Calculate the filling rates of each pipe - The rate of Pipe P = 120 liters / 4 hours = 30 liters/hour - The rate of Pipe Q = 120 liters / 8 hours = 15 liters/hour - The rate of Pipe R = 120 liters / 12 hours = 10 liters/hour - The rate of Pipe S (emptying) = 120 liters / 10 hours = 12 liters/hour ### Step 2: Determine the effective rates for each combination 1. **Option 1: Q alone** - Rate of Q = 15 liters/hour - Time to fill = 120 liters / 15 liters/hour = 8 hours 2. **Option 2: P and S together** - Rate of P = 30 liters/hour - Rate of S = -12 liters/hour (since it empties) - Effective rate = 30 - 12 = 18 liters/hour - Time to fill = 120 liters / 18 liters/hour = 20/3 hours ≈ 6.67 hours 3. **Option 3: P, R, and S together** - Rate of P = 30 liters/hour - Rate of R = 10 liters/hour - Rate of S = -12 liters/hour - Effective rate = 30 + 10 - 12 = 28 liters/hour - Time to fill = 120 liters / 28 liters/hour = 15/7 hours ≈ 2.14 hours 4. **Option 4: P, Q, and S together** - Rate of P = 30 liters/hour - Rate of Q = 15 liters/hour - Rate of S = -12 liters/hour - Effective rate = 30 + 15 - 12 = 33 liters/hour - Time to fill = 120 liters / 33 liters/hour = 120/33 hours ≈ 3.64 hours ### Step 3: Compare the times - Option 1: 8 hours - Option 2: 20/3 hours ≈ 6.67 hours - Option 3: 15/7 hours ≈ 2.14 hours - Option 4: 120/33 hours ≈ 3.64 hours ### Conclusion The arrangement that fills the cistern in the least amount of time is **Option 3: P, R, and S together**, taking approximately 2.14 hours. ---
Promotional Banner

Topper's Solved these Questions

  • PIPE AND CISTERN

    KIRAN PUBLICATION|Exercise TYPE-II|9 Videos
  • PIPE AND CISTERN

    KIRAN PUBLICATION|Exercise TYPE-III|33 Videos
  • PERCENTAGE

    KIRAN PUBLICATION|Exercise TEST YOURSELF|23 Videos
  • POWER, INDICES AND SURDS

    KIRAN PUBLICATION|Exercise Test Yourself|25 Videos

Similar Questions

Explore conceptually related problems

Two pipes A and B can separately empty a cistern in 12 hours and 15 hours respectively. In what time will the cistern be emptied, if both the pipes are opened together ?

A cistern has three pipes A, B and C. A and B can fill it in 3 hrs and 4 hrs respectively while C can empty the completely filled cistern in 1 hour. If the pipes are opened in order at 3 PM., 4 P.M. and 5 P.M. respectively, at what time will the cistern be empty?

A cistern has three pipes A, B and C. A and B can fill it in 3 hrs and 4 hrs respectively while C can empty the completely filled cistern in 1 hour. If the pipes are opened in order at 3 PM., 4 P.M. and 5 P.M. respectively, at what time will the cistern be empty?

Two taps can separately fill a cistern in 10 minutes and 15 minutes respectively and when the waste pipe is opened , they can together fill it in 18 minutes . The waste pipe can empty the full cistern in

Pipes A and B can fill an empty tank in 6 and 8 hours respectively, while pipe C can empty the full tank in 10 hours. If all three pipes are opened together, then the tank will get filled in:

Two pipes can fill a cistern in 28 and 21 hours respectively and an another pipe can empty 30 gallons of water per hour. All the three pipes working together can fill the empty cistern in 84 hours. What is the capacity (in gallons) of the cistern?